The 1960 Iowa State Senate elections took place as part of the biennial 1960 United States elections. Iowa voters elected state senators in 29 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.
A statewide map of the 50 state Senate districts in the year 1960 is provided by the Iowa General Assembly here.
The primary election on June 6, 1960, determined which candidates appeared on the November 8, 1960 general election ballot.
Following the previous election, Republicans had control of the Iowa state Senate with 33 seats to Democrats' 17 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 9 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1960 general election with the balance of power shifting to Republicans holding 35 seats and Democrats having 15 seats (a net gain of 2 seats for Republicans).
Summary of Results
- Note: The 21 holdover Senators not up for re-election are not listed on this table.
Source:
Detailed Results
- NOTE: The 21 districts that did not hold elections in 1960 are not listed here.
- Note: The Iowa Secretary of State's website does not document any competitive intra-party primaries for state Senate races in 1960.
District 2
District 3
District 4
District 5
District 6
District 8
District 11
District 14
District 15
District 16
District 17
District 19
District 23
District 24
District 25
District 26
District 27
District 28
District 31
District 32
District 33
District 36
District 39
District 40
District 41
District 43
District 46
District 47
District 49
See also
- United States elections, 1960
- United States House of Representatives elections in Iowa, 1960
- Elections in Iowa
References
